# Shamu

by
**ryerye123**

Last updated 5 years ago

** Discipline: **

Math ** Subject: **

Calculus
** Grade:**

12

Shamu(Answers in red)

Work done to remove Shamu

Work done to remove water

Fluid pressure on new window (circular)

Fluid pressure on old window (triangular)

3,681,881 ft-lb

394,668 ft-lb

814,301 ft-lb

35000 + 21000 = 56,000 ft-lb

To find fluid pressure: Multiply the water weight by the integral, from bottom to top of tank, of the distance times the area of a horizontal slice. The slice is right minus left using the indirectly given slope and y-intercept.The work done to remove the water is done by finding the equation for the tank which is a semi-circle. The distance from the top of the water to the bottom of the water multiplied by the equation for the semi-circle. Integrate that from the bottom of the tank to the top. That integral is multiplied by the weight of the water (64 lbs/cubic ft.).

Shamu, we want to lift you 100 feet because you deserve a once-in-a-lifetime view of the world around you. Because you are stuck under the water almost all the time, the view will be even more spectacular and provide a new perspective for you. The total work for lifting you out of the water includes a 7 ft/lb cable with a 100 lb loading apparatus. The weight of the cable is variable and the weight of you and the apparatus is constant. We propose replacing your old boring triangular window with a new, classic circular window. This new window will have a greater viewing area, allowing you to make more meaningful connections with your viewers. So many people pass by and don't get a full glimpse of your glory. Many more people can take the time to admire you at the same time with this new window. Don't settle for less when it comes to you and your spectators. You are a superstar and deserve the attention of everyone that passes.

There are no comments for this Glog.