Quadratics Project
by
aarthur
Last updated 7 years ago
Discipline:
Math Subject:
Algebra I
Grade:
7


Real life example:
By BellaMeyerP5
Quadratics project
The space between the legsof the Eiffel tower forms aparabola!
Vertex: 0,4Axis of Symmetry: 0Solutions (X-Intercepts): (-1.1,0) (1.1,0)Y intercept: 4Domain: All realRange: 4 > y
Points0,41,12,-83,-234,-44
The graph opens up at the bottom for thisequation because the "a" value is negative.
AOS: -b / 2(a)For -3x^2+4 a cThere is no b. b = 00/2(-3)0/-60AOS = 0
How to solve quad. by factoring for x intercept.
How to find the vertex:First, you find the axis of symmetry, which is explained in the box to the left. The x coordinate will be your AOS number. Next, you replace all of the x's in the equation with the x intercept. For this example it would be:-3x^2+4-3(0)^2+40+44The vertex is 0,4
Vertex: -4,-1Axis of Symmetry: -4Solutions: (5,0) (3,0)Y intercept: 0,15Domain: All realRange: y > -1
AOS:-b / 2(a)x^2+8x+15 a b c-8 / 2 (1)-8 / 2-4AOS: -4
Points:0,151,242,353,484,63
(-4)^2+8(-4)+1516+-32+1516+-32+15-1-4,-1
The graph opens up at the top because the "a" value is positive.
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