Glog-965
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jenirussell
Last updated 7 years ago
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Babylonian Math
Number Table-2 0; 303 0; 204 0; 155 0; 126 0; 108 0; 7, 309 0; 6, 4010 0; 6
THIER NUMBER BASE IS 60
Formulasab = [(a + b)2 - a2 - b2]/2a/b = a (1/b)1/13 = 7/91 = 7 (1/91) = (approx) 7 (1/90) ax3 + bx2 = c
To divide THey did a/b = a (1/b)
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