Chemical Element

E1 Reactions-unimolecular elimination removes an Hydrogen substituent and results in the formation of a double bond (1)

.E2 Reactions-bimolecular elimination removes a hydrogen from the chemical resulting in the fomation of a double bond, while the leaving group leave and bonds with the hydrogen(5)

The reaction’s rate-determining step is unimolecular E1.Step 1: Protonation of alcohol. Step 2: Dissociation of ion. Step 3:Deprotonation of cation.(6)

E1 and E2 videos courtesy of Khan Academy

Step 1: A base attracks a hydrogen and it attaches to the carbon that doesn't have a leaving group. They hydrogen comes off and the leaving group leaves resulting in a double bond (5)

Carboncation-hydride shift- election from the unimolecular substitution moves over to another carbon-it normally occurs with a rxn of an alcohol or hydrogen halide (HBr, HCl, HF)-happens in E1 rxn(2)

E1 and E2 reactions can be used in the dehydration of alcohols and the dehydrohalogenation of alkyl halidesImportant in preparing of alkenes(1)

E2 mechanism needs at least a moderate leaving group (not poor), and the base must be at least moderate (not weak) E1 depends only on the substrate and it does't have to be a strong base(7)

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