To find the AOS by hand, use the equation -b/2(a)-3x^2+0+4 a b cIf there is no ----- after the 2nd number than add a 0 in the middleThere is no use for c right now-4/ 2(0)AOS= 0

The coefficient has to be positive for the parabola to open up, and negative for the parabola to open down

Vertex:3x^2+4-b/2(a) -0/2(a)=03(0^2)+40+44(0,4)

Vertex: (0,4)Axis of Symmetry:0Solutions (x Intercept): (-1.1,0) (1.1,0)Y Intercepts:4Domain: All Real NumbersRange:y<0

x y1 1 2 -8 3 -234 -445 -71

Parabola ProjectKylie Hinzp: 5

The underside of the rainbow represents amaximum parabola

Vertex: (4,-11)Axis of Symmetry:4Solution:(0.7,0) (7.3,0)Y intercept:(0,5)Domain: All Real NumbersRange:y > -11

x y1 -22 -7 3 -10 4 -11 5 -10

AOS-b/2(a)x^2-8x+5a b c-8/2(1)-8/24

3x^2+4MAXIMUM

-x^2-8x+5MINIMUM

Vertex by Handy=x^2+5-b/2(a)-(-8)/2(1)8/2=4AOS=4Vertex:y=4^2-8(4)+5y=16-32+5y=-11(4,-11)=vertex

The coefficient has to be negative for the parabola to open up.

Solutions(.7,0) (7.3,0)Trace on the calculator to find them

The coefficient has to be negative for the parabola to open up.

Solutions(-1.1,0) (1.1,0)Trace on the calculator to find them

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